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Observation of a 1/3 magnetization plateau in Pb2Cu10O4(SeO3)4Cl7 arising from (Cu2+)7 clusters of corner-sharing (Cu2+)4 tetrahedraстатья Исследовательская статья
Статья опубликована в высокорейтинговом журнале
Статья опубликована в журнале из списка Web of Science и/или Scopus- Авторы: Vasiliev A.N., Berdonosov Peter S., Kozlyakova Ekaterina, Maximova Olga, Murtazoev Alisher F., Dolgikh Valery, Lyssenko Konstantin, Pchelkina Zlata Victorovna, Gorbunov Denis, Chung Seung-Hwan, Koo Hyun-Joo, Whangbo Mike
- Журнал: Dalton Transactions
- Том: 51
- Год издания: 2022
- Издательство: Royal Society of Chemistry
- Местоположение издательства: United Kingdom
- Первая страница: 15017
- Последняя страница: 15021
- DOI: 10.1039/d2dt02316d
- Аннотация: Mixed-valence compound Pb2Cu10O4(SeO3)4Cl7 has a complex structure consisting of one nonmagnetic Cu+ (S=0) ion and four nonequivalent magnetic Cu2+ (S=1/2) ions. It orders antiferromagnetically at TN = 10.2 K. At a temperature below TN, a sequence of spin-flop transition at Bspin-flop = 1.3 T and 1/3 plateau formation at Bspin-flip = 4.4 K is observed in the magnetization curve M(B). The 1/3 magnetization plateau persists at least up to 53.5 T. The spin exchanges of Pb2Cu10O4(SeO3)4Cl7 evaluated by performing the energy-mapping analysis based on DFT+U calculations show that the magnetic properties of Pb2Cu10O4(SeO3)4Cl7 are described by the (Cu2+)7 clusters of corner-sharing (Cu2+)4 tetrahedra, that each (Cu2+)7 cluster has a S = 3/2 spin arrangement in the ground state, and that these ferrimagnetic clusters are coupled antiferromagnetically to form antiferromagnetic (AFM) chains. The 1/3 magnetization plateau observed for Pb2Cu10O4(SeO3)4Cl7 is explained by the field-induced spin flip of every second (Cu2+)7 cluster in each AFM chain.
- Добавил в систему: Козлякова Екатерина Сергеевна